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Chapter 17: Problem 34
A normal distribution has standard deviation \(\sigma=12.3\) points and the 84th percentile of the distribution is \(P_{84}=66.7\) points. (a) Find the median \(\mu\). (b) Find the 16 th percentile \(P_{16}\).
Short Answer
Expert verified
The median (\(\mu\)) is 54.4 and the 16th percentile \(P_{16}\) is 42.1.
Step by step solution
01
Calculate the median (\(\mu\))
Since the value of the 84th percentile is one standard deviation above the mean, we subtract one standard deviation from the P84 value to obtain the mean (\(\mu\)). Hence, \(\mu = P_{84} - \sigma = 66.7 - 12.3 = 54.4)\).
02
Find the 16th percentile \(P_{16}\)
The 16th percentile falls one standard deviation below the mean in a standard normal distribution. Therefore, subtract the standard deviation from the mean. So, \(P_{16} = \mu - \sigma = 54.4 - 12.3 = 42.1\).
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